Python을 이용한 차원 축소 실습 (2)
''' ? ''' 이 있는 부분을 채워주시면 됩니다¶
나는 내 스타일로 하겠다 하시면 그냥 구현 하셔도 됩니다!!
참고하셔야 하는 함수들은 링크 달아드렸으니 들어가서 확인해보세요
1. PCA의 과정
In [1]:
import numpy as np
import numpy.linalg as lin
import matplotlib.pyplot as plt
import pandas as pd
import random
# 기본 모듈들을 불러와 줍니다
In [2]:
x1 = [95, 91, 66, 94, 68, 63, 12, 73, 93, 51, 13, 70, 63, 63, 97, 56, 67, 96, 75, 6]
x2 = [56, 27, 25, 1, 9, 80, 92, 69, 6, 25, 83, 82, 54, 97, 66, 93, 76, 59, 94, 9]
x3 = [57, 34, 9, 79, 4, 77, 100, 42, 6, 96, 61, 66, 9, 25, 84, 46, 16, 63, 53, 30]
# 설명변수 x1, x2, x3의 값이 이렇게 있네요
In [3]:
X = np.stack((x1, x2, x3), axis=0)
# 설명변수들을 하나의 행렬로 만들어 줍니다
In [4]:
X = pd.DataFrame(X.T, columns=['x1', 'x2', 'x3'])
In [5]:
X
Out[5]:
In [6]:
# OR
X = np.stack((x1, x2, x3), axis=1)
pd.DataFrame(X, columns=['x1', 'x2', 'x3']).head()
Out[6]:
1-1) 먼저 PCA를 시작하기 전에 항상 데이터를 scaling 해주어야 해요
In [7]:
from sklearn.preprocessing import StandardScaler
scaler = StandardScaler()
X_std = scaler.fit_transform(X)
In [8]:
X_std
Out[8]:
array([[ 1.08573604, 0.02614175, 0.30684189],
[ 0.93801686, -0.86575334, -0.46445467],
[ 0.01477192, -0.92726334, -1.30282049],
[ 1.04880625, -1.66538341, 1.04460382],
[ 0.08863151, -1.41934339, -1.47049366],
[-0.09601747, 0.76426183, 0.97753455],
[-1.97943714, 1.13332186, 1.74883111],
[ 0.2732805 , 0.42595679, -0.1961776 ],
[ 1.01187645, -1.5116084 , -1.40342439],
[-0.53917504, -0.92726334, 1.61469258],
[-1.94250735, 0.85652683, 0.44098042],
[ 0.16249111, 0.82577183, 0.60865359],
[-0.09601747, -0.03536825, -1.30282049],
[-0.09601747, 1.28709688, -0.76626636],
[ 1.15959564, 0.33369178, 1.21227698],
[-0.35452606, 1.16407687, -0.06203907],
[ 0.05170172, 0.64124181, -1.06807806],
[ 1.12266584, 0.11840676, 0.50804969],
[ 0.3471401 , 1.19483187, 0.17270336],
[-2.20101593, -1.41934339, -0.5985932 ]])
In [9]:
features = X_std.T
In [10]:
features
Out[10]:
array([[ 1.08573604, 0.93801686, 0.01477192, 1.04880625, 0.08863151,
-0.09601747, -1.97943714, 0.2732805 , 1.01187645, -0.53917504,
-1.94250735, 0.16249111, -0.09601747, -0.09601747, 1.15959564,
-0.35452606, 0.05170172, 1.12266584, 0.3471401 , -2.20101593],
[ 0.02614175, -0.86575334, -0.92726334, -1.66538341, -1.41934339,
0.76426183, 1.13332186, 0.42595679, -1.5116084 , -0.92726334,
0.85652683, 0.82577183, -0.03536825, 1.28709688, 0.33369178,
1.16407687, 0.64124181, 0.11840676, 1.19483187, -1.41934339],
[ 0.30684189, -0.46445467, -1.30282049, 1.04460382, -1.47049366,
0.97753455, 1.74883111, -0.1961776 , -1.40342439, 1.61469258,
0.44098042, 0.60865359, -1.30282049, -0.76626636, 1.21227698,
-0.06203907, -1.06807806, 0.50804969, 0.17270336, -0.5985932 ]])
1-2) 자 그럼 공분산 행렬을 구해볼게요
# feature 간의 covariance matrix
cov_matrix = np.cov(features)
In [12]:
cov_matrix
Out[12]:
array([[ 1.05263158, -0.2037104 , -0.12079228],
[-0.2037104 , 1.05263158, 0.3125801 ],
[-0.12079228, 0.3125801 , 1.05263158]])
1-3) 이제 고유값과 고유벡터를 구해볼게요
방법은 실습코드에 있어요!!
In [13]:
# 공분산 행렬의 eigen value, eigen vector
eigenvalues = lin.eig(cov_matrix)[0]
eigenvectors = lin.eig(cov_matrix)[1]
In [14]:
print(eigenvalues)
print(eigenvectors)
# 여기서 eigenvectors는 각 eigen vector가 열벡터로 들어가있는 형태!
# the column v[:,i] is the eigenvector corresponding to the eigenvalue w[i]
# https://numpy.org/doc/1.18/reference/generated/numpy.linalg.eig.html?highlight=eig#numpy.linalg.eig
[1.48756162 0.94435407 0.72597904]
[[ 0.47018528 -0.85137353 -0.23257022]
[-0.64960236 -0.15545725 -0.74421087]
[-0.59744671 -0.50099516 0.62614797]]
In [15]:
# 3*3 영행렬
mat = np.zeros((3, 3))
In [16]:
mat
Out[16]:
array([[0., 0., 0.],
[0., 0., 0.],
[0., 0., 0.]])
In [17]:
# symmetric matrix = P*D*P.T로 분해
mat[0][0] = eigenvalues[0]
mat[1][1] = eigenvalues[1]
mat[2][2] = eigenvalues[2]
print(mat)
[[1.48756162 0. 0. ]
[0. 0.94435407 0. ]
[0. 0. 0.72597904]]
In [18]:
# 혹은 아래와 같이 diagonal matrix를 만들 수 있다
np.diag(eigenvalues)
Out[18]:
array([[1.48756162, 0. , 0. ],
[0. , 0.94435407, 0. ],
[0. , 0. , 0.72597904]])
1-4) 자 이제 고유값 분해를 할 모든 준비가 되었어요 고유값 분해의 곱으로 원래 공분산 행렬을 구해보세요
In [19]:
# P*D*P.T
np.dot(np.dot(eigenvectors, mat), eigenvectors.T)
Out[19]:
array([[ 1.05263158, -0.2037104 , -0.12079228],
[-0.2037104 , 1.05263158, 0.3125801 ],
[-0.12079228, 0.3125801 , 1.05263158]])
In [20]:
cov_matrix
Out[20]:
array([[ 1.05263158, -0.2037104 , -0.12079228],
[-0.2037104 , 1.05263158, 0.3125801 ],
[-0.12079228, 0.3125801 , 1.05263158]])
1-5) 마지막으로 고유 벡터 축으로 값을 변환해 볼게요
함수로 한번 정의해 보았어요
In [21]:
X_std
Out[21]:
array([[ 1.08573604, 0.02614175, 0.30684189],
[ 0.93801686, -0.86575334, -0.46445467],
[ 0.01477192, -0.92726334, -1.30282049],
[ 1.04880625, -1.66538341, 1.04460382],
[ 0.08863151, -1.41934339, -1.47049366],
[-0.09601747, 0.76426183, 0.97753455],
[-1.97943714, 1.13332186, 1.74883111],
[ 0.2732805 , 0.42595679, -0.1961776 ],
[ 1.01187645, -1.5116084 , -1.40342439],
[-0.53917504, -0.92726334, 1.61469258],
[-1.94250735, 0.85652683, 0.44098042],
[ 0.16249111, 0.82577183, 0.60865359],
[-0.09601747, -0.03536825, -1.30282049],
[-0.09601747, 1.28709688, -0.76626636],
[ 1.15959564, 0.33369178, 1.21227698],
[-0.35452606, 1.16407687, -0.06203907],
[ 0.05170172, 0.64124181, -1.06807806],
[ 1.12266584, 0.11840676, 0.50804969],
[ 0.3471401 , 1.19483187, 0.17270336],
[-2.20101593, -1.41934339, -0.5985932 ]])
In [22]:
def new_coordinates(X, eigenvectors):
for i in range(eigenvectors.shape[0]):
if i == 0:
new = [X.dot(eigenvectors.T[i])]
else:
new = np.concatenate((new, [X.dot(eigenvectors.T[i])]), axis=0)
return new.T
# 모든 고유 벡터 축으로 데이터를 projection한 값입니다
In [23]:
X_std
Out[23]:
array([[ 1.08573604, 0.02614175, 0.30684189],
[ 0.93801686, -0.86575334, -0.46445467],
[ 0.01477192, -0.92726334, -1.30282049],
[ 1.04880625, -1.66538341, 1.04460382],
[ 0.08863151, -1.41934339, -1.47049366],
[-0.09601747, 0.76426183, 0.97753455],
[-1.97943714, 1.13332186, 1.74883111],
[ 0.2732805 , 0.42595679, -0.1961776 ],
[ 1.01187645, -1.5116084 , -1.40342439],
[-0.53917504, -0.92726334, 1.61469258],
[-1.94250735, 0.85652683, 0.44098042],
[ 0.16249111, 0.82577183, 0.60865359],
[-0.09601747, -0.03536825, -1.30282049],
[-0.09601747, 1.28709688, -0.76626636],
[ 1.15959564, 0.33369178, 1.21227698],
[-0.35452606, 1.16407687, -0.06203907],
[ 0.05170172, 0.64124181, -1.06807806],
[ 1.12266584, 0.11840676, 0.50804969],
[ 0.3471401 , 1.19483187, 0.17270336],
[-2.20101593, -1.41934339, -0.5985932 ]])
In [24]:
new_coordinates(X_std, eigenvectors)
# 새로운 축으로 변환되어 나타난 데이터들입니다
Out[24]:
array([[ 0.31019368, -1.08215716, -0.07983642],
[ 1.28092404, -0.43132556, 0.13533091],
[ 1.38766381, 0.78428014, -0.12911446],
[ 0.95087515, -1.15737142, 1.6495519 ],
[ 1.84222365, 0.88189889, 0.11493111],
[-1.12563709, -0.52680338, 0.06564012],
[-2.71174416, 0.63290138, 0.71195473],
[-0.03100441, -0.20059783, -0.50339479],
[ 2.29618509, 0.07661447, 0.01087174],
[-0.61585248, -0.205764 , 1.82651199],
[-1.73320252, 1.29971699, 0.09045178],
[-0.82366049, -0.57164535, -0.27123176],
[ 0.75619512, 0.73995175, -0.76710616],
[-0.42344386, 0.26555394, -1.41533681],
[-0.39581307, -1.64646874, 0.24104031],
[-0.88581498, 0.15195119, -0.82271209],
[ 0.24587691, 0.39139878, -1.15801831],
[ 0.14741103, -1.22874561, -0.03110396],
[-0.7161265 , -0.56781471, -0.86180345],
[ 0.24475107, 2.39442622, 1.19337361]])
2. PCA 구현
위의 과정을 이해하셨다면 충분히 하실 수 있을거에요In [25]:
from sklearn.preprocessing import StandardScaler
def MYPCA(X, number):
scaler = StandardScaler()
x_std = scaler.fit_transform(X)
features = x_std.T
cov_matrix = np.cov(features)
eigenvalues = lin.eig(cov_matrix)[0]
eigenvectors = lin.eig(cov_matrix)[1]
new_coordinate = new_coordinates(x_std, eigenvectors)
index = eigenvalues.argsort()[::-1] # 내림차순 정렬한 인덱스
index = list(index)
for i in range(number):
if i==0:
new = [new_coordinate[:, index.index(i)]]
else:
new = np.concatenate(([new, [new_coordinate[:, index.index(i)]]]), axis=0)
return new.T
In [26]:
MYPCA(X,3)
# 새로운 축으로 잘 변환되어서 나타나나요?
# 위에서 했던 PCA랑은 차이가 있을 수 있어요 왜냐하면 위에서는 고유값이 큰 축 순서로 정렬을 안했었거든요
Out[26]:
array([[ 0.31019368, -1.08215716, -0.07983642],
[ 1.28092404, -0.43132556, 0.13533091],
[ 1.38766381, 0.78428014, -0.12911446],
[ 0.95087515, -1.15737142, 1.6495519 ],
[ 1.84222365, 0.88189889, 0.11493111],
[-1.12563709, -0.52680338, 0.06564012],
[-2.71174416, 0.63290138, 0.71195473],
[-0.03100441, -0.20059783, -0.50339479],
[ 2.29618509, 0.07661447, 0.01087174],
[-0.61585248, -0.205764 , 1.82651199],
[-1.73320252, 1.29971699, 0.09045178],
[-0.82366049, -0.57164535, -0.27123176],
[ 0.75619512, 0.73995175, -0.76710616],
[-0.42344386, 0.26555394, -1.41533681],
[-0.39581307, -1.64646874, 0.24104031],
[-0.88581498, 0.15195119, -0.82271209],
[ 0.24587691, 0.39139878, -1.15801831],
[ 0.14741103, -1.22874561, -0.03110396],
[-0.7161265 , -0.56781471, -0.86180345],
[ 0.24475107, 2.39442622, 1.19337361]])
3. sklearn 비교
In [27]:
from sklearn.decomposition import PCA
pca = PCA(n_components=3)
In [28]:
pca.fit_transform(X_std)[:5]
Out[28]:
array([[-0.31019368, -1.08215716, -0.07983642],
[-1.28092404, -0.43132556, 0.13533091],
[-1.38766381, 0.78428014, -0.12911446],
[-0.95087515, -1.15737142, 1.6495519 ],
[-1.84222365, 0.88189889, 0.11493111]])
In [29]:
MYPCA(X, 3)[:5]
Out[29]:
array([[ 0.31019368, -1.08215716, -0.07983642],
[ 1.28092404, -0.43132556, 0.13533091],
[ 1.38766381, 0.78428014, -0.12911446],
[ 0.95087515, -1.15737142, 1.6495519 ],
[ 1.84222365, 0.88189889, 0.11493111]])
In [30]:
pca = PCA(n_components=2)
pca.fit_transform(X_std)[:5]
Out[30]:
array([[-0.31019368, -1.08215716],
[-1.28092404, -0.43132556],
[-1.38766381, 0.78428014],
[-0.95087515, -1.15737142],
[-1.84222365, 0.88189889]])
In [31]:
MYPCA(X, 2)[:5]
Out[31]:
array([[ 0.31019368, -1.08215716],
[ 1.28092404, -0.43132556],
[ 1.38766381, 0.78428014],
[ 0.95087515, -1.15737142],
[ 1.84222365, 0.88189889]])
4. MNIST data에 적용을 해보!
import numpy as np
import numpy.linalg as lin
import matplotlib.pyplot as plt
import pandas as pd
from sklearn.datasets import fetch_openml
from scipy import io
%matplotlib inline
from mpl_toolkits.mplot3d import Axes3D
# mnist 손글씨 데이터를 불러옵니다
In [2]:
mnist = io.loadmat('mnist-original.mat')
X = mnist['data'].T
y = mnist['label'].T
In [3]:
print(X.shape)
print(y.shape)
(70000, 784)
(70000, 1)
In [4]:
np.unique(y)
Out[4]:
array([0., 1., 2., 3., 4., 5., 6., 7., 8., 9.])
In [5]:
# data information
# 7만개의 작은 숫자 이미지
# 행 열이 반대로 되어있음 -> 전치
# grayscale 28x28 pixel = 784 feature
# 각 picel은 0~255의 값
# label = 1~10 label이 총 10개인거에 주목하자
In [6]:
# data를 각 픽셀에 이름붙여 표현
feat_cols = ['pixel'+str(i) for i in range(X.shape[1]) ]
df = pd.DataFrame(X, columns=feat_cols)
df.head()
Out[6]:
5 rows × 784 columnsIn [7]:
# df에 라벨 y를 붙여서 데이터프레임 생성
df['y'] = y
In [8]:
df.head()
Out[8]:
5 rows × 785 columns
지금까지 배운 여러 머신러닝 기법들이 있을거에요
4-1) train_test_split을 통해 데이터를 0.8 0.2의 비율로 분할 해 주시고요
4-2) PCA를 이용하여 mnist data를 축소해서 학습을 해주세요 / test error가 제일 작으신 분께 상품을 드리겠습니다 ^0^
특정한 틀 없이 자유롭게 하시면 됩니다!!!!!!!!!
1. train test split
In [9]:
from sklearn.model_selection import train_test_split
from sklearn.preprocessing import StandardScaler
In [10]:
X_train, X_test, y_train, y_test = train_test_split(df.drop('y', axis=1), df['y'], stratify=df['y'])
In [11]:
standard_scaler = StandardScaler()
standard_scaler.fit(X_train)
X_scaled_train = standard_scaler.transform(X_train)
X_scaled_test = standard_scaler.transform(X_test)
In [43]:
print(X_train.shape)
print(X_test.shape)
print(y_train.shape)
print(y_test.shape)
(52500, 784)
(17500, 784)
(52500,)
(17500,)
In [56]:
print(pd.Series(y_train).value_counts()/len(y_train))
print(pd.Series(y_test).value_counts()/len(y_test))
1.0 0.112533
7.0 0.104190
3.0 0.102019
2.0 0.099848
9.0 0.099390
0.0 0.098610
6.0 0.098229
8.0 0.097505
4.0 0.097486
5.0 0.090190
Name: y, dtype: float64
1.0 0.112514
7.0 0.104171
3.0 0.102000
2.0 0.099886
9.0 0.099429
0.0 0.098629
6.0 0.098229
8.0 0.097486
4.0 0.097486
5.0 0.090171
Name: y, dtype: float64
2. 주성분 개수의 결정
elbow point (곡선의 기울기가 급격히 감소하는 지점)
kaiser's rule (고유값 1 이상의 주성분들)
누적설명률이 70%~80% 이상인 지점
In [13]:
from sklearn.decomposition import PCA
누적설명률이 70%~80%인 지점
In [193]:
variance_ratio = {}
for i in range(80, 200):
if(i%10==0):
print(i)
pca = PCA(n_components=i)
pca.fit(X_scaled_train)
variance_ratio['_'.join(['n', str(i)])] = pca.explained_variance_ratio_.sum()
10
20
30
40
50
60
70
80
90
In [247]:
pca = PCA()
pca.fit(X_scaled_train)
Out[247]:
PCA(copy=True, iterated_power='auto', n_components=None, random_state=None,
svd_solver='auto', tol=0.0, whiten=False)
In [226]:
variance_ratio = []
ratio = 0
for i in np.sort(pca.explained_variance_ratio_)[::-1]:
ratio += i
variance_ratio.append(ratio)
In [243]:
plt.figure(figsize=(12, 5))
plt.plot(list(range(50, 500)), variance_ratio[50:500])
plt.axhline(0.7, color='gray', ls='--')
plt.axhline(0.8, color='gray', ls='--')
plt.axhline(0.9, color='gray', ls='--')
plt.axvline(96, color='black', ls='--')
plt.axvline(146, color='black', ls='--')
plt.axvline(230, color='black', ls='--')
plt.title("VARIANCE RATIO (70%~80%)", size=15)
plt.show()
# scaling한 후
# 96개의 주성분을 선택하면 누적설명률이 70%정도
# 146개의 주성분을 선택하면 누적설명률이 80%정도
# 230개 이상의 주성분을 선택하면 누적설명률이 90%이상 된다.
elbow point
In [248]:
# eigen value를 내림차순으로 정렬한 뒤, plot을 그려보았다.
plt.figure(figsize=(12, 5))
plt.plot(range(1, X.shape[1]+1), np.sort(pca.explained_variance_)[::-1])
plt.show()
# elbow 포인트 지점을 확인하기 위해 0~100 구간을 세밀하게 살펴보도록 한다.
# 확인 결과, 상위 13개의 eigen value를 제외한 나머지 eigen value 사이에는 그다지 큰 차이가 없는 것으로 보인다.
plt.figure(figsize=(12, 5))
plt.plot(range(0, 100), np.sort(pca.explained_variance_)[::-1][0:100])
plt.title('ELBOW POINT', size=15)
plt.axvline(12, ls='--', color='grey')
plt.show()
Kaiser's Rule
In [266]:
# 이번에는 kaiser's rule에 따라 고유값 1 이상의 주성분을 찾아보고자 한다.
# 이를 위해 100~200 구간을 세밀하게 살펴보았으며,
# 그 결과 160개의 주성분을 사용했을 때 eigenvalue가 모두 1 이상이었다.
plt.figure(figsize=(12, 5))
plt.plot(range(100, 200), np.sort(pca.explained_variance_)[::-1][100:200])
plt.title("Kaiser's Rule", size=15)
plt.axhline(1, ls='--', color='grey')
plt.axvline(160, ls='--', color='grey')
plt.show()
# Kaiser's rule에 따라 160개의 주성분을 선택하여 train을 진행해보도록 하겠다.
# (또한 160개의 주성분을 선택하면 원본 데이터의 변동 중 약 82%정도가 설명가능하다.)
In [14]:
pca = PCA(n_components=160)
pca.fit(X_scaled_train)
X_PCA_train = pca.transform(X_scaled_train)
X_PCA_test = pca.transform(X_scaled_test)
3. Modeling
In [15]:
from sklearn.ensemble import RandomForestClassifier
from sklearn.model_selection import GridSearchCV
from sklearn.metrics import *
import time
import warnings
warnings.filterwarnings('ignore')
Random Forest
Original Data
In [290]:
start = time.time()
rf_clf.fit(X_train, y_train)
end = time.time()
print(f'time > {end-start}')
time > 53.27030920982361
In [291]:
pred = rf_clf.predict(X_test)
print(accuracy_score(pred, y_test))
0.9678857142857142
PCA Data
In [271]:
rf_clf = RandomForestClassifier()
In [292]:
start = time.time()
rf_clf.fit(X_PCA_train, y_train)
end = time.time()
print(f'time > {end-start}')
time > 84.94275045394897
In [294]:
pred = rf_clf.predict(X_PCA_test)
print(accuracy_score(pred, y_test))
0.9408571428571428
Logistic Regression
Original Data
In [295]:
from sklearn.linear_model import LogisticRegression
In [296]:
lr_clf = LogisticRegression()
In [307]:
start = time.time()
lr_clf.fit(X_train, y_train)
end = time.time()
print(f'time > {end-start}')
time > 13.492876052856445
In [308]:
pred = lr_clf.predict(X_test)
print(accuracy_score(pred, y_test))
0.9225714285714286
In [338]:
param = {
'C':[0.001, 0.01, 0.1, 1, 10, 100, 1000],
}
grid = GridSearchCV(lr_clf, param, cv=5, scoring='accuracy', verbose=10)
grid.fit(X_train, y_train)
In [340]:
grid.best_score_
Out[340]:
0.918704761904762
PCA Data
In [320]:
start = time.time()
lr_clf.fit(X_PCA_train, y_train)
end = time.time()
print(f'time > {end-start}')
time > 5.322706937789917
In [321]:
# 원본데이터와 accuracy 차이가 크게 나지 않는다!
# 하지만 Random Forest에 비해 accuracy 떨어진다.
pred = lr_clf.predict(X_PCA_test)
print(accuracy_score(pred, y_test))
0.9208
In [342]:
param = {
'C':[0.001, 0.01, 0.1, 1, 10, 100, 1000],
}
grid = GridSearchCV(lr_clf, param, cv=5, scoring='accuracy', verbose=10)
grid.fit(X_PCA_train, y_train)
grid.best_score_
Out[342]:
0.9200571428571429
Decision Tree
Original Data
In [309]:
from sklearn.tree import DecisionTreeClassifier
In [310]:
dt_clf = DecisionTreeClassifier()
In [311]:
start = time.time()
dt_clf.fit(X_train, y_train)
end = time.time()
print(f'time > {end-start}')
time > 24.323933601379395
In [313]:
pred = dt_clf.predict(X_test)
print(accuracy_score(pred, y_test))
0.8713142857142857
PCA data
In [317]:
start = time.time()
dt_clf.fit(X_PCA_train, y_train)
end = time.time()
print(f'time > {end-start}')
time > 23.95996594429016
In [318]:
# PCA한 경우 성능 확연히 떨어진다.
# 또한 Random Forest, Logistic Regression에 비해서 accuracy 너무 낮다.
pred = dt_clf.predict(X_PCA_test)
print(accuracy_score(pred, y_test))
0.8281714285714286
SVM
In [16]:
from sklearn.svm import SVC
svm = SVC()
In [429]:
svm.fit(X_PCA_train, y_train)
Out[429]:
SVC(C=1.0, break_ties=False, cache_size=200, class_weight=None, coef0=0.0,
decision_function_shape='ovr', degree=3, gamma='scale', kernel='rbf',
max_iter=-1, probability=False, random_state=None, shrinking=True,
tol=0.001, verbose=False)
In [431]:
pred = svm.predict(X_PCA_test)
accuracy_score(y_test, pred)
Out[431]:
0.9674857142857143
In [17]:
param = {
'C':[0.001, 0.01, 0.1, 1, 10, 100, 1000],
}
grid = GridSearchCV(svm, param, cv=3, scoring='accuracy', verbose=10, n_jobs=4)
grid.fit(X_PCA_train, y_train)
Fitting 3 folds for each of 7 candidates, totalling 21 fits
[Parallel(n_jobs=4)]: Using backend LokyBackend with 4 concurrent workers.
[Parallel(n_jobs=4)]: Done 5 tasks | elapsed: 30.1min
[Parallel(n_jobs=4)]: Done 10 tasks | elapsed: 36.2min
[Parallel(n_jobs=4)]: Done 17 out of 21 | elapsed: 41.7min remaining: 9.8min
[Parallel(n_jobs=4)]: Done 21 out of 21 | elapsed: 44.6min finished
Out[17]:
GridSearchCV(cv=3, error_score=nan,
estimator=SVC(C=1.0, break_ties=False, cache_size=200,
class_weight=None, coef0=0.0,
decision_function_shape='ovr', degree=3,
gamma='scale', kernel='rbf', max_iter=-1,
probability=False, random_state=None, shrinking=True,
tol=0.001, verbose=False),
iid='deprecated', n_jobs=4,
param_grid={'C': [0.001, 0.01, 0.1, 1, 10, 100, 1000]},
pre_dispatch='2*n_jobs', refit=True, return_train_score=False,
scoring='accuracy', verbose=10)
In [18]:
# hyper parameter tunning을 통해 accuracy를 높였다.
grid.best_score_
Out[18]:
0.9722666666666666
In [19]:
grid.best_params_
Out[19]:
{'C': 10}
XGBoost
In [323]:
from xgboost import XGBClassifier
In [324]:
xgb = XGBClassifier()
In [325]:
start = time.time()
xgb.fit(X_PCA_train, y_train)
end = time.time()
print(f'time > {end-start}')
time > 640.5302169322968
In [326]:
pred = xgb.predict(X_PCA_test)
print(accuracy_score(pred, y_test))
0.9091428571428571
LightGBM
Original Data
In [327]:
from lightgbm import LGBMClassifier
lgbm = LGBMClassifier()
In [331]:
start = time.time()
lgbm.fit(X_train, y_train)
end = time.time()
print(f'time > {end-start}')
time > 153.8949658870697
In [332]:
pred = lgbm.predict(X_test)
print(accuracy_score(pred, y_test))
0.9697142857142858
PCA Data
In [329]:
start = time.time()
lgbm.fit(X_PCA_train, y_train)
end = time.time()
print(f'time > {end-start}')
time > 48.97201323509216
In [330]:
pred = lgbm.predict(X_PCA_test)
print(accuracy_score(pred, y_test))
0.9494285714285714
Stacking (CV)
PCA data
In [432]:
rf_clf = RandomForestClassifier()
lr_clf = LogisticRegression()
lgbm = LGBMClassifier()
svm = SVC()
final_model = LGBMClassifier()
In [439]:
def base_model(model, X_train, X_test, y_train, n_split=5):
# X_train = X_train.reset_index(drop=True)
# X_test = X_test.reset_index(drop=True)
y_train = y_train.reset_index(drop=True)
kfold = KFold(n_splits=n_split)
train_predicted = np.zeros(X_train.shape[0])
test_predicted = np.zeros((n_split, X_test.shape[0]))
for i, (train_index, val_index) in enumerate(kfold.split(X_train)):
print(f'step > {i} ')
train_data = X_train[train_index]
val_data = X_train[val_index]
train_y = y_train[train_index]
model.fit(train_data, train_y)
train_predicted[val_index] = model.predict(val_data)
test_predicted[i] = model.predict(X_test)
test_predicted = test_predicted.mean(axis=0)
return train_predicted, test_predicted
In [397]:
rf_train, rf_test = base_model(rf_clf, X_PCA_train, X_PCA_test, y_train)
lr_train, lr_test = base_model(lr_clf, X_PCA_train, X_PCA_test, y_train)
lgbm_train, lgbm_test = base_model(lgbm, X_PCA_train, X_PCA_test, y_train)
stacking_train = np.stack((rf_train, lr_train, lgbm_train)).T
stacking_test = np.stack((rf_test, lr_test, lgbm_test)).T
# final model로 LGBM 사용
final_model.fit(stacking_train, y_train)
pred = final_model.predict(stacking_test)
print(accuracy_score(y_test, pred)) # 0.9324
# final model로 XGBoost 사용
xgb.fit(stacking_train, y_train)
pred = xgb.predict(stacking_test)
print(accuracy_score(y_test, pred)) # 0.9324
# final model로 Random Forest 사용
rf_clf.fit(stacking_train, y_train)
pred = rf_clf.predict(stacking_test)
print(accuracy_score(y_test, pred)) # 0.9320
step > 0
step > 1
step > 2
step > 3
step > 4
In [440]:
PCA_rf_train, PCA_rf_test = base_model(rf_clf, X_PCA_train, X_PCA_test, y_train)
PCA_lgbm_train, PCA_lgbm_test = base_model(lgbm, X_PCA_train, X_PCA_test, y_train)
PCA_svm_train, PCA_svm_test = base_model(svm, X_PCA_train, X_PCA_test, y_train)
step > 0
step > 1
step > 2
step > 3
step > 4
step > 0
step > 1
step > 2
step > 3
step > 4
step > 0
step > 1
step > 2
step > 3
step > 4
In [441]:
PCA_stacking_train = np.stack((PCA_rf_train, PCA_lgbm_train, PCA_svm_train)).T
PCA_stacking_test = np.stack((PCA_rf_test, PCA_lgbm_test, PCA_svm_test)).T
In [443]:
svm.fit(PCA_stacking_train, y_train)
pred = svm.predict(PCA_stacking_test)
accuracy_score(y_test, pred)
Out[443]:
0.9583428571428572
In [446]:
lgbm.fit(PCA_stacking_train, y_train)
pred = lgbm.predict(PCA_stacking_test)
accuracy_score(y_test, pred)
Out[446]:
0.9577714285714286
In [447]:
PCA_stacking_train = np.stack((PCA_lgbm_train, PCA_svm_train)).T
PCA_stacking_test = np.stack((PCA_lgbm_test, PCA_svm_test)).T
svm.fit(PCA_stacking_train, y_train)
pred = svm.predict(PCA_stacking_test)
accuracy_score(y_test, pred)
Out[447]:
0.9594285714285714
Original Data
In [427]:
rf_train, rf_test = base_model(rf_clf, X_train, X_test, y_train)
lr_train, lr_test = base_model(lr_clf, X_train, X_test, y_train)
lgbm_train, lgbm_test = base_model(lgbm, X_train, X_test, y_train)
step > 0
step > 1
step > 2
step > 3
step > 4
step > 0
step > 1
step > 2
step > 3
step > 4
step > 0
step > 1
step > 2
step > 3
step > 4
In [433]:
stacking_train = np.stack((rf_train, lgbm_train)).T
stacking_test = np.stack((rf_test, lgbm_test)).T
In [434]:
# final model로 LGBM 사용
final_model.fit(stacking_train, y_train)
pred = final_model.predict(stacking_test)
print(accuracy_score(y_test, pred))
# 단일모델보다 결과 안좋다
0.9558285714285715
4. Summary
PCA Data
SVM - 0.9726
Stacking(lgbm+svm & svm) - 0.9594
Stacking(rf+lgbm+svm & svm) - 0.9583
LightGBM - 0.9494
Random Forest - 0.9409
Stacking(rf+lr+lgbm & lgbm) 0.9324
Logistic Regression - 0.9208
XGBoost -> 0.9091
Decision Tree - 0.8282
Original Data
LightGBM -> 0.9697
Random Forest- 0.9679
Stacking (rf+lgbm & lgbm) -> 0.9558
Logistic Regression- 0.9226
Decision Tree- 0.8713
Last updated